hallo kakak²yang baik hati ada yang bisa bantuin gak
soalnya ada di gambar/foto
gw doain yg bantu dapat pahala ☺
soalnya ada di gambar/foto
gw doain yg bantu dapat pahala ☺
[tex]1. \lim_{x \to 3} 2x-8= 2(3)-8 = -2[/tex]
[tex]2. \lim_{x \to 2} \frac{3x-6}{x-2} = \lim_{x \to 2} \frac{3(x-2)}{x-2} = 3[/tex]
[tex]3. \lim_{x \to 3} \frac{x^{2}-9 }{2x^{2} -7x+3} = \lim_{x \to 3} \frac{(x+3)(x-3)}{(2x-1)(x-3)} \\ \lim_{x \to 3} \frac{(x+3)}{(2x-1)} = \frac{3+3}{2(3)-1} =\frac{6}{5} = 1\frac{1}{5} = 1,2[/tex]
Semoga membantu, Shalom!
[answer.2.content]